Помогите,логарифмы lg(2x-5)^2=0
Решение lg(2x-5)^2 = 0 (2x-5)^2 = 10^0 4x^2 - 20x + 25 = 1 4x^2 -20x + 24 = 0 / 4 x^2 - 5x + 6 = 0 x1 = - 1 x2 = 6