0\\\\6^x=1\\6^x=6^0\\x=0\\\\x=0" alt=" \sqrt{37-36^x}-5=6^x\\\sqrt{37-36^x}=5+6^x\\(\sqrt{37-36^x})=(5+6^x)^2\\37-36^x=25+10*6^x+36^x\\2*36^x+10*6^x-12=0\\ 2*6^{2x}+10*6^x-12=0|:2\\6^{2x}+5*6^x-6=0|t=6^x\\t^2+5t-6=0\\t_1=-6\\t_2=1\\\\6^x \neq -6\\6^x>0\\\\6^x=1\\6^x=6^0\\x=0\\\\x=0" align="absmiddle" class="latex-formula">