Упростите выражения : 1)Arcsin(sin 1,2п)= 2)Arccos(cos 17п/5)=

Решите задачу:

$1)\; arcsin(sin1,2\pi)=arcsin(sin\frac{6\pi}{5})=arcsin(sin(\pi +\frac{\pi}{5}))=\\\\=arcsin(-sin\frac{\pi}{5})=-arcsin(sin\frac{\pi}{5})=-\frac{\pi}{5}\\\\2)arccos(cos\frac{17\pi}{5})=arccos(cos(2\pi +\frac{7\pi}{5}))=arccos(cos(\frac{7\pi}{5})=\\\\=arccos(cos(\pi +\frac{2\pi}{5}))=arccos(-cos\frac{2\pi}{5})=\pi -arccos(cos\frac{2\pi}{5})=\\\\=\pi -\frac{2\pi}{5}=\frac{3\pi}{5}$