Найдите sina,cosa,tga, если ctga=5/12. :)
1 + Ctg²a = 1/Sin² a 1/Sin² a = 1 + 25/144 = 169/144 Sin² a = 144/169 Sin a =+- 12/13 Cos a = +-√(1 - 144/169 = +-√25/169 = +- 5/13 Ctg a = 1/tg a = 12/5