2sinx-корень из3=0 ctg x\3 -1 =0 соs(2x -пи\3)=-1

Решите задачу:

$2sinx - \sqrt{3} = 0 \\ \\ sinx = \dfrac{ \sqrt{3} }{2} \\ \\ \boxed{ x = (-1)^{n} \dfrac{ \pi }{3} + \pi n, \ n \in Z}$

$ctg \dfrac{x}{3} -1 = 0 \\ \\ ctg \dfrac{x}{3} = 1 \\ \\ \dfrac{x}{3} = \dfrac{\pi }{4} + \pi n, \ n \in Z \\ \\ \boxed{x = \dfrac{3\pi }{4} + 3 \pi n, \ n \in Z}$

$cos(2x - \dfrac{ \pi }{3}) = -1 \\ \\ 2x - \dfrac{ \pi }{3} = \pi + 2 \pi n, \ n \in Z \\ \\ 2x = \dfrac{4 \pi }{3} + 2 \pi n, \ n \in Z \\ \\ \boxed{ x = \dfrac{2 \pi }{3} + \pi n, \ n \in Z}$