F(x)=x²-5x-1
g(x)=x²+x-5
|f(x)|>|g(x)|⇒f²>g²⇒(f-g)(f+g)>0
(x²-5x-1-x²-x+5)(x²-5x-1+x²+x-5)>0
(4-6x)(2x²-4x-6)>0
-4(3x-2)(x²-2x-3)>0
4(3x-2)(x-3)(x+1)<0<br>x=2/3 x=3 x=-1
_ + _ +
-------------------------------------------------------------
-1 2/3 3
x∈(-∞;-1) U (2/3;3)