Решите уравнение sin2x + 2os^2x= 4sin^2x
Sin2x+2cos²x=4sin²x 2sinx*cosx+2cos²x-4sin²x=0 | :cos²≠0 2tgx+2-4tg²x=0 |: (-2) tg²x-tgx-2=0 tgx=y y²-y-2=0 y₁=2, y₂=-1 1. tgx=2, x₁=arctg2+πn, n∈Z 2. tgx=-1, x₂=-π/4+πn, n∈Z