6*(3+sqrt(2)+sqrt(3))/(4+3sqrt(2))=6*(3+sqrt(2)+sqrt(3))*(4-3sqrt(2))/(16-18)=
=3(3sqrt(2)-4)(3+sqrt(3)+sqrt(2))=3(5sqrt(2)-6-4sqrt(3)+3sqrt(6))
F(x)=5*sqrt(x)*2
F(4)=20
F(1)=10
F(4)-F(1)=10
f'(x)=3^xln3-9*3^(-x)*ln3
3^x-93^(-x)=0
x=1
f(1)=3+3=6
f(-1)=1/3+3^3=27 1/3
F(2)=9+1=10
6+27 1/3=33 1/3
ответ 33 1/3