1) (x³+8):(x²-2x+4) 2)(1+x)(1-x)(1+x²) 3)5x²-3(x+1)(x-1)
1) (x³+8):(x²-2x+4)= 2)(1+x)(1-x)(1+x²)=(1-x²)*(1+x²)=1-x⁴ 3)5x²-3(x+1)(x-1)=5x²-3(x+1)(x-1)= 5x²-3(x²-1) = 5x²-3x²-3 = 2x² - 3.