А) (10-√2)²+3√32=102-20√2+3·4√2=102-8√2 б) (-0,2/9)-6x>0 , -2/(10*9)-6x>0 , 6x<1/45 , x<1/270<br>в) -2≤(3-4x)/2<5 , -4 ≤3-4x<10 , -7≤-4x<7 , -7/4≤x<7/4<br>г) у=√(х+3)/√(11-2х)-3
![y= \frac{\sqrt{x+3}}{\sqrt{11-2x}-3}\\\\OOF:\; \left\{\begin{array}{ccc}x+3 \geq 0&&\\11-2x \geq 0&&\\\sqrt{11-2x}-3\ne 0&&\end{array}\right. \; \left\{\begin{array}{ccc}x \geq -3&&\\x \leq 5,5&&\\\sqrt{11-2x}\ne 3&&\end{array}\right. \\\\11-2x\ne 9\; ,\; \; 2x\ne 2\; ,\; \; x\ne 1\\\\ \left \{ {{-3 \leq x \leq 5,5} \atop {x\ne 1}} \right. \quad \rightarrow \; \; x\in [-3;\; 1) \cup (1;\; 5,5\, ]](https://tex.z-dn.net/?f=y%3D+%5Cfrac%7B%5Csqrt%7Bx%2B3%7D%7D%7B%5Csqrt%7B11-2x%7D-3%7D%5C%5C%5C%5COOF%3A%5C%3B+++%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx%2B3+%5Cgeq+0%26%26%5C%5C11-2x+%5Cgeq+0%26%26%5C%5C%5Csqrt%7B11-2x%7D-3%5Cne+0%26%26%5Cend%7Barray%7D%5Cright.+%5C%3B+++%5Cleft%5C%7B%5Cbegin%7Barray%7D%7Bccc%7Dx++%5Cgeq+-3%26%26%5C%5Cx+%5Cleq+5%2C5%26%26%5C%5C%5Csqrt%7B11-2x%7D%5Cne+3%26%26%5Cend%7Barray%7D%5Cright.+%5C%5C%5C%5C11-2x%5Cne+9%5C%3B+%2C%5C%3B+%5C%3B+2x%5Cne+2%5C%3B+%2C%5C%3B+%5C%3B+x%5Cne+1%5C%5C%5C%5C+%5Cleft+%5C%7B+%7B%7B-3+%5Cleq+x+%5Cleq+5%2C5%7D+%5Catop+%7Bx%5Cne+1%7D%7D+%5Cright.+%5Cquad+%5Crightarrow+%5C%3B+%5C%3B+x%5Cin+%5B-3%3B%5C%3B+1%29+%5Ccup+%281%3B%5C%3B+5%2C5%5C%2C+%5D "y= \frac{\sqrt{x+3}}{\sqrt{11-2x}-3}\\\\OOF:\; \left\{\begin{array}{ccc}x+3 \geq 0&&\\11-2x \geq 0&&\\\sqrt{11-2x}-3\ne 0&&\end{array}\right. \; \left\{\begin{array}{ccc}x \geq -3&&\\x \leq 5,5&&\\\sqrt{11-2x}\ne 3&&\end{array}\right. \\\\11-2x\ne 9\; ,\; \; 2x\ne 2\; ,\; \; x\ne 1\\\\ \left \{ {{-3 \leq x \leq 5,5} \atop {x\ne 1}} \right. \quad \rightarrow \; \; x\in [-3;\; 1) \cup (1;\; 5,5\, ]")