A)f `(x) = 10x^4-3
f `(1) = 10-3=7
б)f `(x) = 0,25*2x-4(-2)x^(-3)=0,5x+8/x^3
f `(2) = 1+1=2
в)f `(x) = 2/2√x+1/x^2=√x+1/x^2
f `(1) = 1+1=2
г)f `(x) = 2x(2x-1)+2(x^2+8)
f `(0) = 0+2(0+8)=16
д)f `(x) = [2x(x+1)-(x^2-3)]/(x+1)^2
f `(0) = [(0-(0-3))/(0+1)]=3/1=3
е)f `(x) = 10*3x*(x^3-2)^9
f `(1) = 10*3(1-2)=30(-1)^9=-30