ОДЗ x-5>0 x>5 log5(x-5)≠0 x-5≠1 x≠6
5х-27>0 5x>27 x>5,4
log5((5x-27)/(x-5))/log5(x-5)>=0
log5(5x-27)/(x-5)>=log5(1)
log5(x-5)>=log5(1)
(5x-27)/(x-5)>=1 (5x-27-x+5)/(x-5)>=0 (4x-22)/(x-5)>=0
(x-5,5)/(x-5)>=0 x>5,5
x-5>=1 x>=6
log5(5x-27)/(x-5)<=log5(1)</p>
log5(x-5)<=log5(1) x-5<=1 x<=6 </p>
(5x-27)/(x-5)<=1 (4x-22)/(x-5)<=0 [5;5,5]</p>
[5;6]
с учетом ОДЗ (5,4;5,5] U (6;∞)